tractor/tests/test_task_broadcasting.py

1393 lines
43 KiB
Python

"""
Broadcast channels for fan-out to local tasks.
"""
from contextlib import (
asynccontextmanager as acm,
)
from functools import partial
from itertools import cycle
import time
from types import SimpleNamespace
from typing import Optional
import warnings
import pytest
import trio
from trio.lowlevel import current_task
import tractor
from tractor.to_asyncio import LinkedTaskChannel
from tractor.trionics import (
broadcast_receiver,
BroadcastReceiveError,
Lagged,
collapse_eg,
)
@tractor.context
async def echo_sequences(
ctx: tractor.Context,
) -> None:
'''Bidir streaming endpoint which will stream
back any sequence it is sent item-wise.
'''
await ctx.started()
async with ctx.open_stream() as stream:
async for sequence in stream:
seq = list(sequence)
for value in seq:
await stream.send(value)
print(f'producer sent {value}')
async def ensure_sequence(
stream: tractor.MsgStream,
sequence: list,
delay: Optional[float] = None,
) -> None:
name = current_task().name
async with stream.subscribe() as bcaster:
assert not isinstance(bcaster, type(stream))
async for value in bcaster:
print(f'{name} rx: {value}')
assert value == sequence[0]
sequence.remove(value)
if delay:
await trio.sleep(delay)
if not sequence:
# fully consumed
break
@acm
async def open_sequence_streamer(
sequence: list[int],
reg_addr: tuple[str, int],
start_method: str,
) -> tractor.MsgStream:
async with tractor.open_nursery(
registry_addrs=[reg_addr],
start_method=start_method,
) as an:
portal = await an.start_actor(
'sequence_echoer',
enable_modules=[__name__],
)
async with portal.open_context(
echo_sequences,
) as (ctx, first):
assert first is None
async with ctx.open_stream(allow_overruns=True) as stream:
yield stream
await portal.cancel_actor()
def test_stream_fan_out_to_local_subscriptions(
reg_addr,
start_method,
):
sequence = list(range(1000))
async def main():
async with open_sequence_streamer(
sequence,
reg_addr,
start_method,
) as stream:
async with trio.open_nursery() as n:
for i in range(10):
n.start_soon(
ensure_sequence,
stream,
sequence.copy(),
name=f'consumer_{i}',
)
await stream.send(tuple(sequence))
async for value in stream:
print(f'source stream rx: {value}')
assert value == sequence[0]
sequence.remove(value)
if not sequence:
# fully consumed
break
trio.run(main)
@pytest.mark.parametrize(
'task_delays',
[
(0.01, 0.001),
(0.001, 0.01),
]
)
def test_consumer_and_parent_maybe_lag(
reg_addr,
start_method,
task_delays,
):
async def main():
sequence = list(range(300))
parent_delay, sub_delay = task_delays
async with open_sequence_streamer(
sequence,
reg_addr,
start_method,
) as stream:
try:
async with (
collapse_eg(),
trio.open_nursery() as tn,
):
tn.start_soon(
ensure_sequence,
stream,
sequence.copy(),
sub_delay,
name='consumer_task',
)
await stream.send(tuple(sequence))
# async for value in stream:
lagged = False
lag_count = 0
while True:
try:
value = await stream.receive()
print(f'source stream rx: {value}')
if lagged:
# re set the sequence starting at our last
# value
sequence = sequence[sequence.index(value) + 1:]
else:
assert value == sequence[0]
sequence.remove(value)
lagged = False
except Lagged:
lagged = True
print(f'source stream lagged after {value}')
lag_count += 1
continue
# lag the parent
await trio.sleep(parent_delay)
if not sequence:
# fully consumed
break
print(f'parent + source stream lagged: {lag_count}')
if parent_delay > sub_delay:
assert lag_count > 0
except Lagged:
# child was lagged
assert parent_delay < sub_delay
trio.run(main)
def test_faster_task_to_recv_is_cancelled_by_slower(
reg_addr,
start_method,
):
'''
Ensure that if a faster task consuming from a stream is cancelled
the slower task can continue to receive all expected values.
'''
async def main():
sequence = list(range(1000))
async with open_sequence_streamer(
sequence,
reg_addr,
start_method,
) as stream:
async with trio.open_nursery() as tn:
tn.start_soon(
ensure_sequence,
stream,
sequence.copy(),
0,
name='consumer_task',
)
await stream.send(tuple(sequence))
# pull 3 values, cancel the subtask, then
# expect to be able to pull all values still
for i in range(20):
try:
value = await stream.receive()
print(f'source stream rx: {value}')
await trio.sleep(0.01)
except Lagged:
print(f'parent overrun after {value}')
continue
print('cancelling faster subtask')
tn.cancel_scope.cancel()
try:
value = await stream.receive()
print(f'source stream after cancel: {value}')
except Lagged:
print(f'parent overrun after {value}')
# expect to see all remaining values
with trio.fail_after(0.5):
async for value in stream:
assert stream._broadcaster._state.recv_ready is None
print(f'source stream rx: {value}')
if value == 999:
# fully consumed and we missed no values once
# the faster subtask was cancelled
break
# await tractor.pause()
# await stream.receive()
print(f'final value: {value}')
trio.run(main)
def test_subscribe_errors_after_close():
async def main():
size = 1
tx, rx = trio.open_memory_channel(size)
async with broadcast_receiver(rx, size) as brx:
pass
try:
# open and close
async with brx.subscribe():
pass
except trio.ClosedResourceError:
assert brx.key not in brx._state.subs
else:
assert 0
trio.run(main)
@pytest.mark.parametrize(
('size', 'sent', 'dropped'),
[
(1, 2, 1),
(3, 5, 2),
],
)
def test_lagged_reports_exact_drop_count(
size: int,
sent: int,
dropped: int,
) -> None:
'''
`Lagged` must report every value outside the retained window.
`BroadcastReceiver.receive_nowait()` previously subtracted the
queue length from an already-invalid deque index without counting
that first displaced value. A one-slot queue therefore claimed it
dropped zero values after two sends. Keep one root receiver idle
while a child subscriber drains every produced value, then prove
the lag error reports the exact overrun and positions the root at
the oldest value still retained by `BroadcastState.queue`.
'''
async def main() -> None:
tx, rx = trio.open_memory_channel(size)
brx = broadcast_receiver(rx, size)
async with brx.subscribe() as fast:
for value in range(sent):
await tx.send(value)
assert await fast.receive() == value
match = rf'dropped `{dropped}` values'
with pytest.raises(Lagged, match=match):
await brx.receive()
assert await brx.receive() == sent - size
trio.run(main)
def test_broadcast_statistics_report_queued_counts() -> None:
'''
`BroadcastState.statistics()` must report counts, not indexes.
Each `BroadcastState.subs` value is the deque index of a
receiver's next unread value, with `-1` meaning caught up. The
statistics API returned these indexes directly, so one queued
value appeared as zero and every positive count was one short.
Keep one root receiver idle while a child synchronously receives
four produced values. Prove the root count advances through one
and three retained values, then remains clamped to the three-slot
retention window after lagging.
Finally install an actual unwaited `trio.Event` in
`BroadcastState.recv_ready` while treating deprecations as errors.
This proves statistics checks `None` explicitly instead of using
deprecated `trio.Event` truthiness.
'''
async def main() -> None:
tx, rx = trio.open_memory_channel(3)
brx = broadcast_receiver(rx, 3)
async with brx.subscribe() as child:
state = brx._state
assert state.statistics()['queued_len_by_task'] == {
brx.key: 0,
child.key: 0,
}
await tx.send(0)
assert await child.receive() == 0
assert state.statistics()['queued_len_by_task'] == {
brx.key: 1,
child.key: 0,
}
for value in range(1, 4):
await tx.send(value)
assert await child.receive() == value
state.recv_ready = (child.key, trio.Event())
with warnings.catch_warnings():
warnings.simplefilter('error', DeprecationWarning)
stats = state.statistics()
assert stats['queued_len_by_task'] == {
brx.key: 3,
child.key: 0,
}
assert stats['tasks_waiting'] == 0
state.recv_ready = None
trio.run(main)
def test_cancelled_reader_diagnostics_are_transient() -> None:
'''
Cancelled-reader diagnostics must not retain stale `Task`s.
`BroadcastState.cancelled` previously accumulated every source
owner cancelled during `BroadcastReceiver.receive()`. Even after
that receiver successfully read again or its subscription closed,
`BroadcastState.statistics()` retained the old `Task`, reporting
stale state and keeping the completed task alive.
Cancel one child's source read under a receiver-local scope and
verify its task is reported. Reuse that same receiver for one
successful read to prove progress clears the entry. Cancel it once
more, then leave the subscription and prove close also removes the
diagnostic while the root receiver remains registered.
'''
async def main() -> None:
tx, rx = trio.open_memory_channel(1)
brx = broadcast_receiver(rx, 1)
cancel_scope = trio.CancelScope()
child_key: int
child_task = None
async with brx.subscribe() as child:
child_key = child.key
async def cancel_source_read() -> None:
nonlocal child_task
child_task = current_task()
with cancel_scope:
await child.receive()
assert cancel_scope.cancelled_caught
async with trio.open_nursery() as nursery:
nursery.start_soon(cancel_source_read)
while brx._state.recv_ready is None:
await trio.lowlevel.checkpoint()
cancel_scope.cancel()
stats = brx._state.statistics()
assert child_task is not None
assert stats['tasks_cancelled'] == {
child_key: child_task,
}
await tx.send(1)
assert await child.receive() == 1
assert not brx._state.cancelled
cancel_scope = trio.CancelScope()
async with trio.open_nursery() as nursery:
nursery.start_soon(cancel_source_read)
while brx._state.recv_ready is None:
await trio.lowlevel.checkpoint()
cancel_scope.cancel()
assert child_key in brx._state.cancelled
assert child_key not in brx._state.cancelled
assert brx.key in brx._state.subs
trio.run(main)
@pytest.mark.parametrize(
'terminal_exc',
[
trio.EndOfChannel(),
RuntimeError('terminal source failure'),
],
ids=['end-of-channel', 'receive-error'],
)
def test_terminal_broadcast_clears_cancelled_tasks(
terminal_exc: Exception,
) -> None:
'''
Terminal broadcast state must release every cancelled `Task`.
A receiver which owned and cancelled a source read can leave its
task in `BroadcastState.cancelled`. If another receiver later gets
EOC or a terminal source failure, no subscriber can make source
progress to clear that stale diagnostic. Clearing only the terminal
owner's key therefore retained the first receiver's completed task.
Cancel a child during the first controlled source read, then let
the root own a second read which raises EOC or `RuntimeError`.
Prove each terminal path clears the other receiver's diagnostic
before propagating its exact source outcome.
'''
class TerminalReceiver:
'''
Block one cancellable read, then raise a terminal outcome.
'''
def __init__(self) -> None:
self.calls = 0
self.first_started = trio.Event()
async def receive(self) -> None:
'''
Drive cancellation followed by terminal source state.
'''
self.calls += 1
if self.calls == 1:
self.first_started.set()
await trio.sleep_forever()
raise terminal_exc
async def main() -> None:
source = TerminalReceiver()
brx = broadcast_receiver(source, 1)
cancel_scope = trio.CancelScope()
async with brx.subscribe() as child:
async def cancel_child_read() -> None:
with cancel_scope:
await child.receive()
assert cancel_scope.cancelled_caught
async with trio.open_nursery() as nursery:
nursery.start_soon(cancel_child_read)
await source.first_started.wait()
cancel_scope.cancel()
assert child.key in brx._state.cancelled
with pytest.raises(type(terminal_exc)) as exc_info:
await brx.receive()
assert exc_info.value is terminal_exc
assert not brx._state.cancelled
trio.run(main)
def test_end_of_channel_is_terminal_for_waiting_peer() -> None:
'''
EOC must not let an awakened peer re-enter the closed source.
`BroadcastState.eoc` was set when one source owner received EOC,
but neither receive path consulted it. A peer waiting behind that
owner therefore woke, saw no queued value, and started a second
source read. Cancellation at that checkpoint could repopulate
`BroadcastState.cancelled` after the broadcast became terminal.
Block one child in the sole source read while the root waits on its
event, then release EOC. Both receivers must terminate from that
one source call, and the root's later receive must replay EOC
immediately without retaining cancellation diagnostics.
'''
class EOCReceiver:
'''
Publish one controlled EOC and reject any second source read.
'''
def __init__(self) -> None:
self.calls = 0
self.started = trio.Event()
self.release = trio.Event()
async def receive(self) -> None:
'''
Block the only valid source read until EOC release.
'''
self.calls += 1
assert self.calls == 1
self.started.set()
await self.release.wait()
raise trio.EndOfChannel
async def main() -> None:
source = EOCReceiver()
brx = broadcast_receiver(source, 1)
outcomes: list[str] = []
async with brx.subscribe() as child:
async def receive_eoc(
receiver,
name: str,
) -> None:
with pytest.raises(trio.EndOfChannel):
await receiver.receive()
outcomes.append(name)
async with trio.open_nursery() as nursery:
nursery.start_soon(receive_eoc, child, 'child')
await source.started.wait()
nursery.start_soon(receive_eoc, brx, 'root')
_, event = brx._state.recv_ready
while not event.statistics().tasks_waiting:
await trio.lowlevel.checkpoint()
source.release.set()
with pytest.raises(trio.EndOfChannel):
await brx.receive()
assert sorted(outcomes) == ['child', 'root']
assert source.calls == 1
assert not brx._state.cancelled
trio.run(main)
def test_msgstream_eoc_close_preserves_aclose_override() -> None:
'''
Internal EOC cleanup must preserve the public `aclose()` contract.
Passing a new private keyword from `MsgStream.receive()` to
`self.aclose()` broke subclasses whose compatible override kept
the original zero-argument signature. Use a minimal subclass which
records virtual dispatch and delegates to the base implementation.
Drive graceful EOC through the real root broadcaster and prove the
override runs without closing that active root re-entrantly.
'''
class Stream(tractor.MsgStream):
'''
Record public close dispatch with the established signature.
'''
close_calls = 0
async def aclose(self):
'''
Delegate closure without accepting private arguments.
'''
self.close_calls += 1
return await super().aclose()
class PldRx:
'''
Delegate source receive and terminate the close drain.
'''
def __init__(self, rx) -> None:
self._rx = rx
async def recv_pld(self, **kwargs):
'''
Receive directly from the test source channel.
'''
return await self._rx.receive()
def recv_msg_nowait(self, **kwargs):
'''
Report EOC to finish `MsgStream.aclose()` draining.
'''
raise trio.EndOfChannel
async def main() -> None:
tx, rx = trio.open_memory_channel(1)
ctx = SimpleNamespace(
cid='test-context',
_pld_rx=PldRx(rx),
send_stop=lambda: trio.lowlevel.checkpoint(),
side='caller',
peer_side='callee',
maybe_raise=lambda **kwargs: None,
)
stream = Stream(ctx, rx)
async with stream.subscribe():
await tx.aclose()
with pytest.raises(trio.EndOfChannel):
await stream.receive()
assert stream.close_calls == 1
assert not stream._broadcaster._closed
trio.run(main)
@pytest.mark.parametrize(
'close_wrapper',
[
tractor.MsgStream.aclose,
LinkedTaskChannel.aclose,
],
ids=['msg-stream', 'linked-task-channel'],
)
def test_wrapper_close_clears_root_cancelled_task(
close_wrapper,
) -> None:
'''
Public stream close must release root cancellation diagnostics.
Root broadcasters allocated by `MsgStream.subscribe()` and
`LinkedTaskChannel.subscribe()` are private implementation state.
If their source receive was cancelled, callers had no public way
to close the root, so wrapper teardown retained the completed
`Task` in `BroadcastState.cancelled` indefinitely.
Cancel a root source read, attach that broadcaster to a minimal
public wrapper, and close it through each real `aclose()` method.
The root receiver and its task diagnostic must both be removed;
for `MsgStream`, pre-close the source to cover its idempotent early
return path.
'''
async def main() -> None:
_, rx = trio.open_memory_channel(1)
brx = broadcast_receiver(rx, 1)
cancel_scope = trio.CancelScope()
async def cancel_source_read() -> None:
with cancel_scope:
await brx.receive()
assert cancel_scope.cancelled_caught
async with trio.open_nursery() as nursery:
nursery.start_soon(cancel_source_read)
while brx._state.recv_ready is None:
await trio.lowlevel.checkpoint()
cancel_scope.cancel()
assert brx.key in brx._state.cancelled
if close_wrapper is tractor.MsgStream.aclose:
ctx = SimpleNamespace(cid='test-context')
wrapper = tractor.MsgStream(ctx, rx)
wrapper._broadcaster = brx
await rx.aclose()
else:
wrapper = SimpleNamespace(
_broadcaster=brx,
_from_aio=rx,
)
await close_wrapper(wrapper)
assert brx.key not in brx._state.subs
assert brx.key not in brx._state.cancelled
trio.run(main)
def test_broadcast_rejects_zero_buffer_size() -> None:
'''
A broadcaster must retain at least one value for peer fan-out.
`collections.deque(maxlen=0)` silently discards every appended
value, so `broadcast_receiver(..., 0)` allowed the source owner to
receive while peer cursors advanced into an always-empty queue.
Their lag recovery then reset to index `-1` and recursively retried
without any retained value to consume.
Construct a rendezvous memory channel and prove broadcaster setup
rejects its zero capacity synchronously with a clear public error,
before any receiver is registered or source receive can begin.
'''
_, rx = trio.open_memory_channel(0)
with pytest.raises(
ValueError,
match='`max_buffer_size` must be greater than zero',
):
broadcast_receiver(rx, 0)
def test_underlying_receive_failure_wakes_all_subscribers() -> None:
'''
A shared receive failure must terminate every broadcast receiver.
Previously, only `EndOfChannel` and receiver cancellation woke
peer tasks waiting on `BroadcastState.recv_ready`. If the shared
underlying receiver raised another error, its owner propagated
the failure and cleared the event while every peer remained
blocked forever.
Script one successful receive followed by a controlled
`RuntimeError`. Let a fast child own both underlying receives
while the root first drains its retained value and then waits on
the child's second receive. Release the failure only after both
tasks have reached those positions. Both exact errors prove the
peer was awakened without losing buffered data. A later
subscriber proves the terminal failure remains published for new
receivers instead of retrying the failed underlying channel.
'''
class FailingReceiver:
'''
Return one value, then fail after deterministic release.
'''
def __init__(self) -> None:
self.calls: int = 0
self.failure_started = trio.Event()
self.release_failure = trio.Event()
async def receive(self) -> int:
'''
Drive the scripted success-then-failure sequence.
'''
self.calls += 1
if self.calls == 1:
return 1
self.failure_started.set()
await self.release_failure.wait()
raise RuntimeError('underlying receive failed')
async def main() -> None:
source = FailingReceiver()
brx = broadcast_receiver(source, 3)
child_error: list[RuntimeError] = []
root_error: list[BroadcastReceiveError] = []
late_error: list[BroadcastReceiveError] = []
root_drained = trio.Event()
async def receive_child() -> None:
async with brx.subscribe() as child:
assert await child.receive() == 1
try:
await child.receive()
except RuntimeError as exc:
child_error.append(exc)
async def receive_root() -> None:
assert await brx.receive() == 1
root_drained.set()
try:
await brx.receive()
except BroadcastReceiveError as exc:
root_error.append(exc)
with trio.fail_after(1):
async with trio.open_nursery() as nursery:
nursery.start_soon(receive_child)
await source.failure_started.wait()
nursery.start_soon(receive_root)
await root_drained.wait()
source.release_failure.set()
assert source.calls == 2
assert [str(exc) for exc in child_error] == [
'underlying receive failed',
]
assert [str(exc) for exc in root_error] == [
'Shared broadcast receiver failed',
]
assert child_error[0] is not root_error[0]
assert root_error[0].__cause__ is child_error[0]
async with brx.subscribe() as late:
with pytest.raises(
BroadcastReceiveError,
match='Shared broadcast receiver failed',
) as exc_info:
await late.receive()
late_error.append(exc_info.value)
assert late_error[0] is not child_error[0]
assert late_error[0] is not root_error[0]
assert late_error[0].__cause__ is child_error[0]
assert source.calls == 2
trio.run(main)
def test_control_flow_exit_wakes_broadcast_peer() -> None:
'''
Non-terminal control flow must wake peers without being retained.
Process-control and cancellation-like `BaseException` values
should remain local to the task which receives them, but the old
owner still has to wake subscribers blocked on its shared event.
Make one child own a controlled `BaseException` receive while the
root waits behind it. After release, prove the child gets that
exact exit and the root takes ownership of the next underlying
receive instead of hanging or replaying the control-flow event.
'''
class ReceiveExit(BaseException):
'''
Model a non-terminal process-control receive exit.
'''
class ControlFlowReceiver:
'''
Raise one controlled exit, then return a value.
'''
def __init__(self) -> None:
self.calls: int = 0
self.exit_started = trio.Event()
self.release_exit = trio.Event()
async def receive(self) -> int:
'''
Drive the scripted control-flow-then-value sequence.
'''
self.calls += 1
if self.calls == 1:
self.exit_started.set()
await self.release_exit.wait()
raise ReceiveExit
return 2
async def main() -> None:
source = ControlFlowReceiver()
brx = broadcast_receiver(source, 3)
child_exit: list[ReceiveExit] = []
root_value: list[int] = []
async def receive_child() -> None:
async with brx.subscribe() as child:
try:
await child.receive()
except ReceiveExit as exc:
child_exit.append(exc)
async def receive_root() -> None:
root_value.append(await brx.receive())
with trio.fail_after(1):
async with trio.open_nursery() as nursery:
nursery.start_soon(receive_child)
await source.exit_started.wait()
nursery.start_soon(receive_root)
while True:
_, event = brx._state.recv_ready
if event.statistics().tasks_waiting:
break
await trio.lowlevel.checkpoint()
source.release_exit.set()
assert len(child_exit) == 1
assert root_value == [2]
assert source.calls == 2
assert brx._state.receive_exc is None
trio.run(main)
def test_closing_non_owner_preserves_source_wait() -> None:
'''
Closing one subscriber must not wake another receiver's peers.
`BroadcastReceiver.aclose()` previously set the one shared
`BroadcastState.recv_ready` event even when a different receiver
owned the source read. Waiting peers then repeatedly awaited an
already-set event until the source produced another value,
creating a runnable hot loop on idle streams.
Block one child in the source receive, then place both the root
and a closing child behind its event. Close only that waiting
child and prove it gets `ClosedResourceError` without setting the
shared event. Both remaining receivers must still get the same
value after the source is released.
'''
async def main() -> None:
tx, rx = trio.open_memory_channel(1)
brx = broadcast_receiver(rx, 3)
owner_value: list[int] = []
root_value: list[int] = []
closing_closed = trio.Event()
async with (
brx.subscribe() as owner,
brx.subscribe() as closing,
):
async def receive_owner() -> None:
owner_value.append(await owner.receive())
async def receive_root() -> None:
root_value.append(await brx.receive())
async def receive_closing() -> None:
with pytest.raises(trio.ClosedResourceError):
await closing.receive()
closing_closed.set()
with trio.fail_after(1):
async with trio.open_nursery() as nursery:
nursery.start_soon(receive_owner)
while brx._state.recv_ready is None:
await trio.lowlevel.checkpoint()
nursery.start_soon(receive_root)
nursery.start_soon(receive_closing)
_, event = brx._state.recv_ready
while event.statistics().tasks_waiting < 2:
await trio.lowlevel.checkpoint()
await closing.aclose()
await closing_closed.wait()
assert not event.is_set()
await tx.send(1)
assert owner_value == [1]
assert root_value == [1]
trio.run(main)
@pytest.mark.parametrize(
'first_outcome',
[
1,
RuntimeError('discarded source error'),
trio.EndOfChannel(),
],
)
def test_closing_source_owner_hands_read_to_peer(
first_outcome: int|Exception,
) -> None:
'''
Closing the source-read owner must transfer ownership to a peer.
Merely suppressing the old shared-event wake would leave peers
blocked behind an externally closed receiver that still owned an
idle source read. Script a first receive which blocks until its
private scope is cancelled and a second which returns immediately.
Close that owner only after the root is waiting behind it. Cover
a shielded value, ordinary error and EOC from the cancelled source
read. The owner must always get `ClosedResourceError`, while the
awakened root takes the second source read without publishing the
discarded source outcome.
'''
class HandoffReceiver:
'''
Block the first source read and satisfy the second.
'''
def __init__(self) -> None:
self.calls: int = 0
self.first_started = trio.Event()
self.release_first = trio.Event()
async def receive(self) -> int:
'''
Drive one cancelled read followed by one value.
'''
self.calls += 1
if self.calls == 1:
self.first_started.set()
with trio.CancelScope(shield=True):
await self.release_first.wait()
if isinstance(first_outcome, BaseException):
raise first_outcome
return first_outcome
return 2
async def main() -> None:
source = HandoffReceiver()
brx = broadcast_receiver(source, 3)
owner_closed = trio.Event()
root_value: list[int] = []
async with brx.subscribe() as owner:
async def receive_owner() -> None:
with pytest.raises(trio.ClosedResourceError):
await owner.receive()
owner_closed.set()
async def receive_root() -> None:
root_value.append(await brx.receive())
with trio.fail_after(1):
async with trio.open_nursery() as nursery:
nursery.start_soon(receive_owner)
await source.first_started.wait()
nursery.start_soon(receive_root)
_, event = brx._state.recv_ready
while not event.statistics().tasks_waiting:
await trio.lowlevel.checkpoint()
await owner.aclose()
source.release_first.set()
await owner_closed.wait()
assert source.calls == 2
assert root_value == [2]
assert brx._state.receive_exc is None
assert not brx._state.eoc
trio.run(main)
def test_ensure_slow_consumers_lag_out(
reg_addr,
start_method,
):
'''This is a pure local task test; no tractor
machinery is really required.
'''
async def main():
# make sure it all works within the runtime
async with tractor.open_root_actor():
num_laggers = 4
laggers: dict[str, int] = {}
retries = 3
size = 100
tx, rx = trio.open_memory_channel(size)
brx = broadcast_receiver(rx, size)
async def sub_and_print(
delay: float,
) -> None:
task = current_task()
start = time.time()
async with brx.subscribe() as lbrx:
while True:
print(f'{task.name}: starting consume loop')
try:
async for value in lbrx:
print(f'{task.name}: {value}')
await trio.sleep(delay)
if task.name == 'sub_1':
# trigger checkpoint to clean out other subs
await trio.sleep(0.01)
# the non-lagger got
# a ``trio.EndOfChannel``
# because the ``tx`` below was closed
assert len(lbrx._state.subs) == 1
await lbrx.aclose()
assert len(lbrx._state.subs) == 0
except trio.ClosedResourceError:
# only the fast sub will try to re-enter
# iteration on the now closed bcaster
assert task.name == 'sub_1'
return
except Lagged:
lag_time = time.time() - start
lags = laggers[task.name]
print(
f'restarting slow task {task.name} '
f'that bailed out on {lags}:{value} '
f'after {lag_time:.3f}')
if lags <= retries:
laggers[task.name] += 1
continue
else:
print(
f'{task.name} was too slow and terminated '
f'on {lags}:{value}')
return
async with trio.open_nursery() as tn:
for i in range(1, num_laggers):
task_name = f'sub_{i}'
laggers[task_name] = 0
tn.start_soon(
partial(
sub_and_print,
delay=i*0.001,
),
name=task_name,
)
# allow subs to sched
await trio.sleep(0.1)
async with tx:
for i in cycle(range(size)):
await tx.send(i)
if len(brx._state.subs) == 2:
# only one, the non lagger, sub is left
break
# the non-lagger
assert laggers.pop('sub_1') == 0
for n, v in laggers.items():
assert v == 4
assert tx._closed
assert not tx._state.open_send_channels
# check that "first" bcaster that we created
# above, never was iterated and is thus overrun
try:
await brx.receive()
except Lagged:
# expect tokio style index truncation
seq = brx._state.subs[brx.key]
assert seq == len(brx._state.queue) - 1
# all no_overruns entries in the underlying
# channel should have been copied into the bcaster
# queue trailing-window
async for i in rx:
print(f'bped: {i}')
assert i in brx._state.queue
# should be noop
await brx.aclose()
trio.run(main)
def test_first_recver_is_cancelled():
async def main():
# make sure it all works within the runtime
async with tractor.open_root_actor():
tx, rx = trio.open_memory_channel(1)
brx = broadcast_receiver(rx, 1)
cs = trio.CancelScope()
async def sub_and_recv():
with cs:
async with brx.subscribe() as bc:
async for value in bc:
print(value)
assert cs.cancelled_caught
async def cancel_and_send():
await trio.sleep(0.2)
cs.cancel()
await tx.send(1)
async with trio.open_nursery() as n:
n.start_soon(sub_and_recv)
await trio.sleep(0.1)
assert brx._state.recv_ready
n.start_soon(cancel_and_send)
# ensure that we don't hang because no-task is now
# waiting on the underlying receive..
with trio.fail_after(0.5):
value = await brx.receive()
print(f'parent: {value}')
assert value == 1
trio.run(main)
def test_no_raise_on_lag():
'''
Run a simple 2-task broadcast where one task is slow but configured
so that it does not raise `Lagged` on overruns using
`raise_on_lasg=False` and verify that the task does not raise.
'''
size = 100
tx, rx = trio.open_memory_channel(size)
brx = broadcast_receiver(rx, size)
async def slow():
async with brx.subscribe(
raise_on_lag=False,
) as br:
async for msg in br:
print(f'slow task got: {msg}')
await trio.sleep(0.1)
async def fast():
async with brx.subscribe() as br:
async for msg in br:
print(f'fast task got: {msg}')
async def main():
async with (
tractor.open_root_actor(
# NOTE: so we see the warning msg emitted by the bcaster
# internals when the no raise flag is set.
loglevel='warning',
),
collapse_eg(),
trio.open_nursery() as n,
):
n.start_soon(slow)
n.start_soon(fast)
for i in range(1000):
await tx.send(i)
# simulate user nailing ctl-c after realizing
# there's a lag in the slow task.
await trio.sleep(1)
raise KeyboardInterrupt
with pytest.raises(KeyboardInterrupt):
trio.run(main)
@pytest.mark.parametrize(
('subscribe', 'chan_attr'),
[
(tractor.MsgStream.subscribe, '_rx_chan'),
(LinkedTaskChannel.subscribe, '_from_aio'),
],
ids=['msg-stream', 'linked-task-channel'],
)
def test_stream_subscribe_forwards_lag_policy(
subscribe,
chan_attr: str,
) -> None:
'''
Stream wrappers must expose per-subscriber lag policy.
`MsgStream.subscribe()` and `LinkedTaskChannel.subscribe()`
previously omitted `BroadcastReceiver.raise_on_lag`, forcing
downstream users to mutate a private receiver attribute. Invoke
each public wrapper against a minimal receive-compatible handle.
Prove the first non-raising subscription configures both the
irreversible root broadcaster and its child, while a later strict
child selects its own policy without changing that root.
'''
class StreamHandle:
'''
Provide the wrapper fields needed for local fan-out.
'''
def __init__(self) -> None:
self._broadcaster = None
setattr(
self,
chan_attr,
SimpleNamespace(
_state=SimpleNamespace(max_buffer_size=1),
),
)
async def receive(self):
'''
Block if a regression unexpectedly enters source receive.
'''
await trio.sleep_forever()
async def send(self, value) -> None:
'''
Satisfy `MsgStream` duplex-handle patching.
'''
async def main() -> None:
stream = StreamHandle()
async with subscribe(
stream,
raise_on_lag=False,
) as first:
assert not stream._broadcaster._raise_on_lag
assert not first._raise_on_lag
async with subscribe(
stream,
raise_on_lag=True,
) as second:
assert not stream._broadcaster._raise_on_lag
assert second._raise_on_lag
trio.run(main)